If $\sum\limits_{i = 1}^{18} {(x_i - 8) = 9}$ and $\sum\limits_{i = 1}^{18} {(x_i - 8)^2 = 45}$,then the standard deviation of $x_1, x_2, \dots, x_{18}$ is:

  • A
    $4/9$
  • B
    $9/4$
  • C
    $3/2$
  • D
    None of these

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Similar Questions

All the students of a class performed poorly in Mathematics. The teacher decided to give grace marks of $10$ to each of the students. Which of the following statistical measures will not change even after the grace marks were given?

Students of two sections $A$ and $B$ of a class show the following results in a test conducted for $100$ marks. Then
Section $A$ Section $B$
Number of students $50$ $60$
Average marks in the test $45$ $45$
Variance of distribution of marks $64$ $81$

The frequency distribution is given below:
$\begin{array}{|l|l|l|l|l|l|l|} \hline X & 2 & 3 & 4 & 5 & 6 & 7 \\ f & 4 & 9 & 16 & 14 & 11 & 6 \\ \hline \end{array}$
Find the standard deviation.

In a data set with $15$ observations $x_1, x_2, x_3, \ldots, x_{15}$,we are given $\sum_{i=1}^{15} x_i^2 = 3600$ and $\sum_{i=1}^{15} x_i = 175$. If the value of one observation $20$ was found to be incorrect and was replaced by its correct value $40$,then the corrected variance of the data is:

The variance of $^{10}C_0, ^{10}C_1, ^{10}C_2, \dots, ^{10}C_{10}$ is:

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